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Section 5.6 Antiderivatives (Integration)
Subsection 5.6.1 Inspection and Substitution
Checkpoint 5.6.1.
Use the inspection method to find the general antiderivative:
\(\int (6x^2 - 4x + 5) \, dx\)
Checkpoint 5.6.2.
Evaluate using substitution:
\(\int 2x e^{x^2} \, dx\)
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\(\frac{1}{2}e^{x^2} + C\)
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Checkpoint 5.6.3.
By inspection, find the antiderivative of
\(f(x) = \sec^2(x) + \sin(x)\text{.}\)
\(\tan(x) - \cos(x) + C\)
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\(\tan(x) + \cos(x) + C\)
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Checkpoint 5.6.4.
Find
\(\int \cos(3x) \, dx\text{.}\)
\(\frac{1}{3}\sin(3x) + C\)
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Checkpoint 5.6.5.
Evaluate
\(\int \frac{(\ln x)^2}{x} \, dx\) using
\(u = \ln x\text{.}\)
\(\frac{1}{3}(\ln x)^3 + C\)
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\(\frac{1}{2}(\ln x)^2 + C\)
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Checkpoint 5.6.6.
Find the antiderivative:
\(\int 2x(x^2 + 5)^4 \, dx\)
\(\frac{1}{5}(x^2 + 5)^5 + C\)
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\(\frac{1}{4}(x^2 + 5)^4 + C\)
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Checkpoint 5.6.7.
Find
\(\int e^{\sin(x)} \cos(x) \, dx\)
Checkpoint 5.6.8.
Evaluate
\(\int \frac{\ln(x)}{x} \, dx\)
\(\frac{1}{2}(\ln(x))^2 + C\)
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Checkpoint 5.6.9.
Find
\(\int x \sqrt{x^2 + 1} \, dx\)
\(\frac{1}{3}(x^2 + 1)^{3/2} + C\)
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\(\frac{2}{3}(x^2 + 1)^{3/2} + C\)
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\(\frac{1}{2}(x^2 + 1)^{1/2} + C\)
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Checkpoint 5.6.10.
Evaluate
\(\int \cos(3x) \, dx\)
\(\frac{1}{3}\sin(3x) + C\)
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\(-\frac{1}{3}\sin(3x) + C\)
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Subsection 5.6.2 Integration by Parts and Partial Fractions
Checkpoint 5.6.11.
Evaluate
\(\int \frac{1}{(x-1)(x+2)} \, dx\)
\(\frac{1}{3}\ln|x-1| - \frac{1}{3}\ln|x+2| + C\)
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\(\ln|x-1| + \ln|x+2| + C\)
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\(\frac{1}{3}\ln|x-1| + \frac{1}{3}\ln|x+2| + C\)
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Checkpoint 5.6.12.
Find
\(\int \frac{x+5}{x^2+x-2} \, dx\)
\(2\ln|x-1| - \ln|x+2| + C\)
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\(\ln|x-1| + 2\ln|x+2| + C\)
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\(2\ln|x+1| - \ln|x-2| + C\)
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Checkpoint 5.6.13.
Evaluate
\(\int \frac{1}{x^2-4} \, dx\)
\(\frac{1}{4}\ln\left|\frac{x-2}{x+2}\right| + C\)
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\(\frac{1}{2}\ln\left|\frac{x-2}{x+2}\right| + C\)
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Checkpoint 5.6.14.
Find
\(\int \frac{2x}{(x+1)^2} \, dx\)
\(2\ln|x+1| + \frac{2}{x+1} + C\)
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\(2\ln|x+1| - \frac{2}{x+1} + C\)
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Checkpoint 5.6.15.
Evaluate
\(\int \frac{1}{x^2+x} \, dx\)
\(\ln|x| - \ln|x+1| + C\)
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\(\ln|x+1| - \ln|x| + C\)
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Checkpoint 5.6.16.
Find
\(\int x e^x \, dx\)
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\(\frac{1}{2}x^2 e^x + C\)
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Checkpoint 5.6.17.
Evaluate
\(\int x \sin(x) \, dx\)
\(-x\cos(x) + \sin(x) + C\)
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\(x\cos(x) - \sin(x) + C\)
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\(-x\sin(x) + \cos(x) + C\)
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Checkpoint 5.6.18.
Find
\(\int \ln(x) \, dx\)
Checkpoint 5.6.19.
Evaluate
\(\int x^2 \ln(x) \, dx\)
\(\frac{x^3}{3}\ln(x) - \frac{x^3}{9} + C\)
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\(\frac{x^3}{3}\ln(x) - \frac{x^3}{3} + C\)
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Checkpoint 5.6.20.
Find
\(\int \arctan(x) \, dx\)
\(x\arctan(x) - \frac{1}{2}\ln(1+x^2) + C\)
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\(x\arctan(x) + \frac{1}{2}\ln(1+x^2) + C\)
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Checkpoint 5.6.21.
Use integration by parts to evaluate:
\(\int x e^x \, dx\)
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\(\frac{1}{2}x^2 e^x + C\)
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Hint.
Correct! Use integration by parts with
\(u = x\text{,}\) \(dv = e^x dx\text{.}\)
Incorrect. Remember:
\(\int u\,dv = uv - \int v\,du\text{.}\)
Checkpoint 5.6.22.
Evaluate the following antiderivative:
\(\int \ln(x) \, dx\)
Checkpoint 5.6.23.
Use partial fraction decomposition to find:
\(\int \frac{1}{x^2 - 1} \, dx\)
\(\frac{1}{2}\ln|x-1| - \frac{1}{2}\ln|x+1| + C\)
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\(\frac{1}{2}\ln|x+1| - \frac{1}{2}\ln|x-1| + C\)
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Checkpoint 5.6.24.
What is the correct form of the partial fraction decomposition for the integrand
\(\frac{5x}{(x-2)(x^2+1)}\text{?}\)
\(\frac{A}{x-2} + \frac{Bx+C}{x^2+1}\)
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\(\frac{A}{x-2} + \frac{B}{x^2+1}\)
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\(\frac{Ax+B}{x-2} + \frac{Cx+D}{x^2+1}\)
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Checkpoint 5.6.25.
Evaluate using integration by parts:
\(\int x \cos(x) \, dx\)
\(x \sin(x) + \cos(x) + C\)
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\(x \sin(x) - \cos(x) + C\)
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\(-x \sin(x) + \cos(x) + C\)
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