Exercises 2.6 Exercise
2.
Evaluate the Following Limits
-
\begin{equation*} \lim_{x \to 2} (3x + 1) \end{equation*}
-
\begin{equation*} \lim_{x \to -1} \frac{x^2 - 1}{x + 1} \end{equation*}
-
\begin{equation*} \lim_{x \to 3} \frac{x^2 - 9}{x - 3} \end{equation*}
-
\begin{equation*} \lim_{x \to 0} \frac{2x^2 + x}{x} \end{equation*}
-
\begin{equation*} \lim_{x \to 4} \sqrt{x} \end{equation*}
Answer.
3.
Use \(\epsilon\text{,}\) \(\delta\) definition of limit to prove the following limits:
-
\begin{equation*} \lim_{x \to 3} (4x-1) = 11 \end{equation*}
-
\begin{equation*} \lim_{x \to 4} x^2 = 16 \end{equation*}
-
\begin{equation*} \lim_{x \to 2} \frac{x}{7}=\frac{2}{7} \end{equation*}
-
\begin{equation*} \lim_{x \to 2} (3x-2)=4 \end{equation*}
-
\begin{equation*} \lim_{x \to -1} (5x+8)=3 \end{equation*}
4.
How close to \(2 \) do we have to take \(x\) so that \(4x-5\) is within a distance of (a) \(0.1\) and (b) \(0.01\) from \(3\text{?}\)
5.
Answer: 2.
6.
7.
8.
Evaluate:
-
\begin{equation*} \lim_{x \to 4} (5x^2-2x+3) \end{equation*}
-
\begin{equation*} \lim_{x \to 1} \frac{x^2 - 1}{x - 1} \end{equation*}
-
\begin{equation*} \lim_{x \to -1} \frac{x-2}{x^2+4x-3} \end{equation*}
-
\begin{equation*} \lim_{x \to 1} \frac{x^2 +x-2}{x^2-3x+2} \end{equation*}
-
\begin{equation*} \lim_{t \to 0} \frac{\sqrt{2-t}-\sqrt{2}}{t} \end{equation*}
-
\begin{equation*} \lim_{x \to 1} \frac{t^3-1}{t^2-1} \end{equation*}
-
\begin{equation*} \lim_{x \to 2} \frac{x-\sqrt{3x-2}}{x^2-4} \end{equation*}
-
\begin{equation*} \lim_{x \to 4} \frac{x-4}{\sqrt{x}-2} \end{equation*}
9.
Let
\begin{equation*}
f(x) = \begin{cases} x+1; & x \lt 0 \\ 3x-5; & x \geq 0 \end{cases}
\end{equation*}
then find
-
\begin{equation*} \lim_{x \to 0^-} f(x) \end{equation*}
-
\(\displaystyle \lim_{x \to 0^{+}} f(x)\)
-
\begin{equation*} \lim_{x \to 0} f(x) \end{equation*}
Explain if the limit exists or not.
10.
11.
12.
Evaluate LHL and RHL of the given function:
-
\begin{equation*} f(x) = \begin{cases} \frac{|x-4|}{x-4}; & x\neq 4 \\ 0; & x=4 \end{cases} \,\quad \text {at } \, x=4. \end{equation*}
-
\begin{equation*} f(x) = \begin{cases} 1+x^2; & \text{ if } \, 0 \leq x \leq 1 \\ 2-x; & \text{ if }\, x \gt 1 \end{cases} \,\quad \text {at } \, x=1. \end{equation*}
13.
-
\begin{equation*} \text{ If } f(x) = \begin{cases} 5x-4; & 0 \lt x \leq 1 \\ 4x^3-3x; & 1 \lt x \lt 2 \end{cases} \end{equation*}then show that \(\lim_{x \to 1} f(x)\) exist.
-
Prove that\begin{equation*} \lim_{x \to 0^+} \sqrt{x} \cos^4 x =0 \end{equation*}
14.
15.
Hint.
16.
Evaluate the function at \(a=3.\)
\begin{equation*}
\lim_{x\to a} f(x)= \lim_{x\to a} \frac{x+1}{x-3}
\end{equation*}
17.
Evaluate:
\begin{equation*}
\lim_{x\to 1} f(x)= \lim_{x\to 1} \left[-\frac{1}{(x-1)^2}\right]
\end{equation*}
18.
Find the relationship between \(a\) and \(b\) so that the function \(f\) defined by
\begin{equation*}
f(x) = \begin{cases}
ax+1; & \text{for } x\leq 3 \\
bx+1; & \text{for } x \gt 3 \\
\end{cases}
\end{equation*}
is continuous at \(x=3.\)
19.
Evaluate:
-
\begin{equation*} \lim_{z\to 1} \frac{(5-z)^2-25}{z} \end{equation*}
-
\begin{equation*} \lim_{r\to 0} \frac{1}{r}\left(\frac{1}{r+3}-\frac{1}{3}\right) \end{equation*}
-
\begin{equation*} \lim_{r\to 1} \frac{\sqrt{x+3}-2}{x-1} \end{equation*}
-
\begin{equation*} \lim_{r\to -5} \frac{2x+10}{|x+5|} \end{equation*}
Hint.
20.
Find all points of discontinuity of \(f\text{,}\) where
\begin{equation*}
f(x) = \begin{cases} \frac{\sin x}{x} & x \lt 0 \\
x+1 & x \geq 0 \end{cases}.
\end{equation*}
21.
Examine the following funcitons for the continuity
-
\begin{equation*} f(x)=x-5 \end{equation*}
-
\begin{equation*} f(x)=\frac{1}{x-5}; \, x\neq 5 \end{equation*}
-
\begin{equation*} f(x)=\frac{x^2-25}{x+5}; \, x\neq -5 \end{equation*}
-
\begin{equation*} f(x)=\lvert x-5 \rvert \end{equation*}
22.
\begin{equation*}
\lim_{x\to 5} \frac{\sqrt{4x+5}-5}{\sqrt{x-1}-2}
\end{equation*}
Answer: 8/5.
23.
\begin{equation*}
\lim_{x\to \infty} \frac{2x^2+x-5}{4x^3+5x+1}
\end{equation*}
24.
\begin{equation*}
\lim_{x\to \infty} \frac{3x^5+5x^3+2}{2x^3+x-1}
\end{equation*}
25.
\begin{equation*}
\lim_{x\to \infty} \frac{-2x^4+5x^2+x+1}{5x^3+x-2}
\end{equation*}
26.
27.
Calculate:
-
\begin{equation*} \lim_{x\to 0} x\cot x \end{equation*}
-
\begin{equation*} \lim_{x\to 0} \frac{\sin 3x}{5x^3-4x} \end{equation*}
28.
Evaluate \(f(x)\text{:}\) If
-
\begin{equation*} f(x) = \begin{cases} x^2-4; & x\lt 2 \\ 3x-2; & x\geq 2 \end{cases} \end{equation*}
-
\begin{equation*} f(x) = \begin{cases} x^2+3x; & x\lt 0 \\ 3x+4; & x\geq 0 \end{cases} \end{equation*}
-
\begin{equation*} f(x) = \begin{cases}2x+5; & x\lt -1 \\ -x+3; & -1\leq x \lt 2 \\ x^2-4x+7; & x \geq 2 \end{cases} \end{equation*}
29.
Evaluate the following:
-
\begin{equation*} \lim_{x\to \infty} \frac{3x^5+5x^3+2}{2x^3+x-1} \end{equation*}
-
\begin{equation*} \lim_{x\to -\infty} \frac{2x^3+x+1}{1-x-x^3} \end{equation*}
-
\begin{equation*} \lim_{x\to 2} \frac{x^2-3x+2}{x^2-4} \end{equation*}
-
\begin{equation*} \lim_{x\to 1} \frac{x^3-1}{x^6-1} \end{equation*}
-
\begin{equation*} \lim_{x\to 1} \frac{x^{\frac{1}{3}}-1}{x^2-1} \end{equation*}
-
\begin{equation*} \lim_{x\to 0} \frac{\sqrt{x+1} -1}{x } \end{equation*}
-
\begin{equation*} \lim_{x\to 0} \frac{\sin 3x}{x} \end{equation*}
-
\begin{equation*} \lim_{x\to 0} \frac{1-\cos 2x}{x^2} \end{equation*}
-
\begin{equation*} \lim_{x\to 0} \frac{\ln (1+x^2)}{1-\cos x} \end{equation*}
-
\begin{equation*} \lim_{x\to 0} \frac{\sin (\sin x)}{x} \end{equation*}
-
\begin{equation*} \lim_{x \to \frac{\pi}{2}} {\tan^{-1} \lfloor \cos x \rfloor} \end{equation*}
30.
Find points of discontinuity if any in the following functions:
-
\begin{equation*} f(x) = \begin{cases} x+1; & x\geq 1 \\ x^2+1; & x \lt 1 \end{cases} \end{equation*}
-
\begin{equation*} f(x) = \begin{cases} \frac{x}{|x|}; & x \lt 0 \\ -1; & x\geq 0 \end{cases} \end{equation*}
31.
-
Determine if \(f(x) = \frac{x^2-4}{x-2}\) is contunous at \(x=2.\)
-
Determine if \(g(x) = \frac{1}{x-3}\) is contunous at \(x=3.\)
-
Show that the function \(f(x) = x^2 \) is contunous.
-
Let\begin{equation*} f(x) = \begin{cases} \frac{1-\cos 4x}{x^2} & x \lt 0 \\ a & x=0 \\ \frac{\sqrt{x}}{\sqrt{16+\sqrt{x}}-4} & x \gt 0 \end{cases} \end{equation*}Determine the value of \(a\) so that \(f(x)\) is continuous at \(x=0\text{.}\)
-
Let\begin{equation*} f(x) = \begin{cases} \frac{(e^x-1)^3\csc (ax)}{\ln (1+x^2)} & x \neq 0 \\ b & x=0 \end{cases} \end{equation*}is continuous, then prove \(ab =1\text{.}\)
-
Let\begin{equation*} f(x) = \begin{cases} (1+3x)^{1/x} & x \neq 0 \\ e^3 & x=0 \end{cases} \end{equation*}Discuss the continuity of \(f(x)\) at \(x=0\text{.}\)
-
Let\begin{equation*} f(x) = \begin{cases} (\cos x)^{\cot^2 x} & x \neq 0 \\ e^{-1/2} & x=0 \end{cases} \end{equation*}Find whether the function \(f(x)\) is continuous at \(x=0\text{.}\)
32.
Evaluate:
\begin{equation*}
\lim_{x\to 0} \frac{(e^{x^2} -1)\ln(1+\sin^2 x)}{(1-\cos 2 x)^2}
\end{equation*}
\begin{equation*}
= \lim_{x\to 0} \frac{(e^{x^2} -1)\ln(1+\sin^2 x)}{(2\sin 2 x)^2}
\end{equation*}
\begin{equation*}
= \lim_{x\to 0} \frac{(e^{x^2} -1)}{(x)^2}\times \frac{\ln(1+\sin^2 x)}{\sin^2 x} \times \frac{x^2}{4\sin^2 x} = 1/4.
\end{equation*}
33.
Answer: (Yes β polynomial, continuous everywhere.)
34.
Answer: (No, undefined at \(x = 3\text{.}\))
35.
Check continuity at \(x = 0\text{:}\)
\begin{equation*}
h(x) = \begin{cases} x^2+1 & x \leq 0 \\ 2x+1 & x \gt 0 \end{cases}
\end{equation*}
36.
For what value of \(k\) is the function continuous at \(x = 2\text{?}\)
\begin{equation*}
f(x) = \begin{cases} 3x-1 & x \lt 2 \\ k & x = 2 \\ x+4 & x \gt 2 \end{cases}
\end{equation*}
Hint.
37.
Answer: (Yes,absolute value is continuous everywhere.)
38.
Find and classify all discontinuities: \(f(x)=\frac{x^2-1}{x-1}\)
39.
Show that the function \(f(x) = \cos x^2\) is continuous.
Hint.
Take a point \(x=c\) where the function is continuous. Then, at \(x=c,\) \(f(x)=f(c)=\cos c^2\)
\begin{equation*}
\lim_{x\to c^-} f(x)= \lim_{h\to 0} \cos (c-h)^2 =\cos c^2.
\end{equation*}
and
\begin{equation*}
\lim_{x\to c^+} f(x)= \lim_{h\to 0} \cos (c+h)^2 =\cos c^2.
\end{equation*}
i.e., the given function is continuous at \(x=c.\)
40.
Discuss the continuity of
\begin{equation*}
f(x)= \begin{cases} x^2+2 & x \lt 0 \\
3x+2 & 0\leq x \lt 1 \\
3e^x-2 & x\geq 1 \end{cases} \, \text{ at } x=0, x=1.
\end{equation*}
41.
42.
Let \(\lfloor t \rfloor \) denote the greatest integer \(\leq t\) and \(\lim_{x\to 0} x\lfloor \frac{4}{x}\rfloor =A.\) The function \(f(x)= \lfloor x^2 \rfloor \sin \pi x\) is discontinuous when \(x=?\)
Hint.
43.
Discuss the continuity of the following functions
-
\begin{equation*} f(x)= \begin{cases} 1 & \text { if } x \leq 0 \\ 2 & \text { if } x \gt 0 \end{cases} \end{equation*}
-
\begin{equation*} f(x)= \begin{cases} 1 & \text { if } x \neq 0 \\ 2 & \text { if } x = 0 \end{cases} \end{equation*}
-
\begin{equation*} f(x)= \begin{cases} -x & \text { if } x \lt 0 \\ x & \text { if } x \geq 0 \end{cases} \end{equation*}
