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Exercises 1.12 Exercise

Sage Plot.

3.

Find the domain of the following functions
  1. \begin{equation*} f(x) =\frac{x-2}{3-x} \end{equation*}
  2. \begin{equation*} f(x) = \sqrt{4-x^2} \end{equation*}
  3. \begin{equation*} f(x) =\frac{1}{\sqrt{1-x}} \end{equation*}
  4. \begin{equation*} f(x) =\sqrt{4-x}+\frac{1}{\sqrt{x^2-1}} \end{equation*}
  5. \begin{equation*} f(x) = \sqrt[3]{t-1} \end{equation*}
  6. \begin{equation*} g(x) = \sqrt{5-2x} \end{equation*}
  7. \begin{equation*} f(x) = \frac{x^4}{x^2+4x-5} \end{equation*}

4.

Draw graph of the given function \(f(x)=\log_2{x-1}\) and find its domain and Range.

5.

Find the domain of
\begin{equation*} f(x) = \frac{1}{\sqrt{4x-x^2}} \end{equation*}
Answer.
\(4 \lt x \lt 0\text{.}\) Domain: (0,4)

6.

Find the domain and sketch the graph of the following functions:
  1. \begin{equation*} f(x) = \sqrt{2x-3} \end{equation*}
  2. \begin{equation*} f(x) = \frac{1}{x+1} \end{equation*}
  3. \begin{equation*} f(x) = \sqrt{-\frac{1}{x}} \end{equation*}
  4. \begin{equation*} f(x) = \frac{1}{(x^2-1)} \end{equation*}
  5. \begin{equation*} f(x) = \sqrt[3]{x} \end{equation*}
  6. \begin{equation*} f(x) = \sqrt[4]{x} \end{equation*}
  7. \begin{equation*} y=\frac{x^2-1}{x^2+1} \end{equation*}
    Hint.
    \begin{equation*} x = \pm \sqrt{-\frac{(1+y)}{(y-1)}} \end{equation*}
    Define function,
    \begin{equation*} -\frac{(1+y)}{(y-1)} \geq 0 \end{equation*}
    \begin{equation*} or, \, \frac{(1+y)}{(y-1)} \leq 0 \end{equation*}
    \begin{equation*} \Rightarrow \,y \in [-1,1) \end{equation*}

7.

Find the domain and sketch the graph of the following functions:
  1. \begin{equation*} f(x) = \sqrt{-x} \end{equation*}
  2. \begin{equation*} h(x) = |2x-1| \end{equation*}
  3. \begin{equation*} f(x) = \frac{x}{|x|} \end{equation*}
  4. \begin{equation*} f(x) = \frac{x^2+x-6}{x+2} \end{equation*}
  5. \begin{equation*} f(x) = \begin{cases} 1-x^2; & \text{ if } x\leq 2 \\ 3x-5 & \text{ if } x\gt 2 \end{cases} \end{equation*}

10.

Graph each function:
  1. \(\displaystyle y=-\frac{1}{x}\)
  2. \(\displaystyle y=\tan 2x\)
  3. \(\displaystyle y=\cos \frac{x}{2}\)
  4. \(\displaystyle y=\sqrt[3]{x+2}\)
  5. \(\displaystyle y=2-\cos x\)
  6. \(\displaystyle y=-2\sin \pi x\)
  7. \(\displaystyle y=\frac{2}{x-3}\)
  8. \(\displaystyle y=2+\frac{1}{x+1}\)
  9. \(\displaystyle y=|\sin x|\)
  10. \(\displaystyle y=(x-1)^3+1\)
  11. \(\displaystyle y=2-\sqrt{x+2}\)

11.

  1. Part A: Multiple Choice (2 points each)
    1. What is the domain of \(f(x) = \sqrt{4 - x}\text{?}\)
      1. \(\displaystyle x \geq -4\)
      2. \(\displaystyle x \leq 4\)
      3. \(\displaystyle x \geq 4\)
      4. All real numbers
    2. The range of \(g(x) = 3x^2 - 12\) is:
      Answer.
    3. Find the domain of \(h(x) = \frac{5}{x+7}.\)
    4. For \(f(x) = \sqrt[3]{x-5}\text{,}\) the domain and range are:
    5. The function \(k(x) = \frac{1}{(x-2)(x+4)}\) has domain:
    6. What is the range of \(y = -2(x+3)^2 + 5\text{?}\)
    7. The domain of \(f(x) = \ln(7 - 4x)\) is:
    8. For the piecewise function \(f(x) =\begin{cases} x+1 & x \lt -\frac{2}{4} & -2 \leq x \lt \frac{3}{x^2} - 5 & x \geq 3 \end{cases}\) the range is:
  2. Part B: Free Response (show work, 5 points each)
    1. Find the domain and range of \(f(x) = \sqrt{9 - x^2}\text{.}\) Write in interval notation.
      Answer.
      domain = [-3, 3]
      range = [0, 3]
    2. Find the domain of \(g(x) = \frac{\sqrt{x+5}}{x^2 - 16}\text{.}\) Write in interval notation.
      Answer.
      Domain: \([-5, -4) \cup (-4, 4) \cup (4, \infty)\)
    3. Find the domain and range of \(h(x) = 2^{x-3} + 1\)
    4. For the function \(y = -3\sqrt{4-x} + 2\text{,}\) state the domain and range in interval notation.

14.

Find the range of:
  1. \begin{equation*} y = \frac{x^2+x+1}{x^2-x+1} \end{equation*}
  2. \begin{equation*} y = \frac{x^2+x+2}{x^2+x+1} \end{equation*}
  3. \begin{equation*} y = \frac{x^2-5x+6}{x^2-3x+2} \end{equation*}
Solution.
  1. Hint.
    change the equation in quadratic in \(x\text{.}\) Now quadratic equations in \(x\) are defined for \(D \geq 0.\)
    Answer.
    \(y\in (-\infty, \frac{1}{3}]\cup [3,\infty)\)
  2. \(\displaystyle 1\lt y \leq \frac{7}{3}\)
  3. \(\displaystyle y\in \mathbb R \setminus \{1,2\}\)

17.

Find the functions \(f\circ g, \, g\circ f, \, f\circ f, \, g\circ g\) and their domains.
\begin{equation*} f(x) = x^2, \, g(x) = 1-\sqrt{x} \end{equation*}

18.

Find the \(f\circ g\circ h\) and their domains.
\begin{equation*} f(x) = x-2, \, g(x) = \sqrt{x}, \, h(x) = x-1 \end{equation*}

19.

Plot the function and its inverse:
\begin{equation*} f(x) = \frac{x^2+5x+6}{x+2} \end{equation*}

20.

Draw graph and state the domain and range of
  1. \begin{equation*} y=\sqrt{9-x^2} \end{equation*}
  2. \begin{equation*} y=\sqrt{x-1} \end{equation*}
  3. \begin{equation*} y=|2x| \end{equation*}
  4. \begin{equation*} y=\frac{1}{x-4} \end{equation*}
  5. \begin{equation*} y=|2x|-1 \end{equation*}
Answer.
  1. \begin{equation*} x\in [-3,3]; \, y \in [0,3] \end{equation*}
  2. \begin{equation*} x\in [1,\infty); \, y \in [0,\infty) \end{equation*}
  3. \begin{equation*} x\in (-\infty,\infty); \, y \in [0,\infty) \end{equation*}
  4. \begin{equation*} x\in \mathbb R \setminus \{4\}; \, y \in \mathbb R \setminus \{0\} \end{equation*}
  5. \begin{equation*} x\in \mathbb R; \, y \in [-1, \infty) \end{equation*}

21.

Draw graph of \(y=\sin x, \, |\sin x|, \, \sin |x|, \, \text { and } \, |y| =\sin x. \)