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Ladder l (m)
5
Rate dx/dt (cm/s)
6
foot distance x
0.00 m
height y on wall
— m
dy/dt (rate ↓)
— cm/s
Pythagoras:
x² + y² = l²
→ differentiate:
2x·(dx/dt) + 2y·(dy/dt) = 0
Answer:
dy/dt = −(x · dx/dt) / √(l² − x²)